To make a 2M solution, we need 2 moles of sucrose per liter of solution. So, we need to calculate the mass of sucrose required for 1L of 2M solution. 3. Mass = moles × molecular mass Mass = 2 moles × 342.3 g/mol = 684.6 g So, to make a 1L 2M sucrose solution, we need **684.6 g** of sucrose.
The normality of a 2.0 M NaOH solution is the same as its molarity, which is 2.0 N. The normality of a solution is defined as the number of equivalents of solute per liter of solution.
Sodium Hydroxide Solution, 2M, Chem-Lab is a strong base and is highly caustic. It is used to increase the alkalinity of a mixture, to neutralize acids and to make sodium salts. One liter of the solution includes 80g of NaOH.
Mass of NaOH = m o l e × m o l a r m a s s = 2 m o l × 40 g / m o l = 80 g . Therefore,80 g of NaOH are needed to make a 2.00 molal solution.
2 mol/L NaOH means that there is the amount of substance of 2 mol NaOH in a volume of one liter. Since NaOH has the rounded molar mass of M(NaOH) = 40 g/mol, there are therefore 80 g of NaOH in one liter.
And 500 mL of 2M NaOH solution contains 80.02g NaOH=40.0 g of NaOH . So, If we mix 40.0 g of NaOH with enough distilled water to make 500 mL, we will get a 2.00 M NaOH solution.
Answer and Explanation:
Therefore, the concentration of the NaOH soluton as a mass/volume percent is 8.0 % N a O H .
Inserted into the formula this means: N = M *1 With NaOH it is always true that M = N, so a one molar solution is equal to a normal one.
To prepare 1N NaOH we have to dissolve 4.0grm NaOH to 100ml water. For 2N NaOH we have to dissolve 4×2=8grm of NaOH to 100 ml water. Thus by dissolving 8grm of NaOH in 100ml of water we will get 2N NaOH solution.
Final answer:
The pH of a 2.0M NaOH solution is calculated by finding the pOH (-log[OH¯]) first, then subtracting that value from 14. The resulting pH of this solution is 14.301.
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